![]() It takes the string to be parsed as its input and returns the. IF your input is String then I recommend you to store the String into a double and then convert the double to the long. The parseFloat() method is a static method of Float class used to convert string to float in java. That gets rid of useless object creation. In order to fix this, use trim (): Long.valueOf (im ()) I would recommend you to use LongparseLong instead of LongvalueOf as it returns long instead of Long. in C or Java code, and hexadecimal strings produced by Cs a format character or. Modifying your example: String s '1333073704000' long l Long.parseLong (s) // Now l 1333073704000. There are a few ways to convert String to long: 1) long l Long.parseLong('200') String numberAsString '1234' long number Long.valueOf(numberAsString).longValue() String numberAsString '1234' Long longObject new Long(numberAsString) long number longObject. However, Long.valueOf () only works strings that only consist of numbers. tested for truth value, and converted to a string (with the repr(). Whenever the getAsString function is called of timeConverter I am getting number format exception at line long timeMillis=Long.parseLong(time) I want to convert the given string to long.ฤก) Here is my timeConverter class package com. The method for converting a string to a long is Long.parseLong.
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